If the Coefficients of the Polynomial 
  | 
(1) | 
 
are specified to be Integers, then integral Roots must have a Numerator which is a
factor of 
 and a Denominator which is a factor of 
 (with either sign possible).  This follows since a
Polynomial of Order 
 with 
 integral Roots can be expressed as
  | 
(2) | 
 
where the Roots are 
, 
, ..., and 
.  Factoring out the
s,
  | 
(3) | 
 
Now, multiplying through,
  | 
(4) | 
 
where we have not bothered with the other terms. Since the first and last Coefficients are 
 and
, all the integral roots of (1) are of the form [factors of 
]/[factors of 
].
 
© 1996-9 Eric W. Weisstein 
1999-05-25